X^2+19x+104=-2x

Solution for X^2+19x+104=-2x equation:

X^2+19X+104=-2X

We move all terms to the left:

X^2+19X+104-(-2X)=0

We get rid of parentheses

X^2+19X+2X+104=0

We add all the numbers together, and all the variables

X^2+21X+104=0

a = 1; b = 21; c = +104;
Δ = b2-4ac
Δ = 212-4·1·104
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-5}{2*1}=\frac{-26}{2}
=-13
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+5}{2*1}=\frac{-16}{2}
=-8
$